320=2x^2+12x

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Solution for 320=2x^2+12x equation:


Simplifying
320 = 2x2 + 12x

Reorder the terms:
320 = 12x + 2x2

Solving
320 = 12x + 2x2

Solving for variable 'x'.

Reorder the terms:
320 + -12x + -2x2 = 12x + -12x + 2x2 + -2x2

Combine like terms: 12x + -12x = 0
320 + -12x + -2x2 = 0 + 2x2 + -2x2
320 + -12x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
320 + -12x + -2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(160 + -6x + -1x2) = 0

Factor a trinomial.
2((10 + -1x)(16 + x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(10 + -1x)' equal to zero and attempt to solve: Simplifying 10 + -1x = 0 Solving 10 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1x = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1x = 0 + -10 -1x = 0 + -10 Combine like terms: 0 + -10 = -10 -1x = -10 Divide each side by '-1'. x = 10 Simplifying x = 10

Subproblem 2

Set the factor '(16 + x)' equal to zero and attempt to solve: Simplifying 16 + x = 0 Solving 16 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = 0 + -16 Combine like terms: 16 + -16 = 0 0 + x = 0 + -16 x = 0 + -16 Combine like terms: 0 + -16 = -16 x = -16 Simplifying x = -16

Solution

x = {10, -16}

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